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1 point) Suppose the flight time between Montreal and Toronto follows a normal distribution with an average of 60 minutes and a standard deviation of 4 minutes. Mary is taking a flight tomorrow morning between these two cities. What is the probability that Mary's flight time will be between 49 minutes and 63 minutes? □
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Expert Verified Solution
0.77039
1 Calculate the z-score for 49 minutes using the formula , where x is the value of interest, is the mean, and is the standard deviation. So, for 49 minutes, the z-score is
2 Calculate the z-score for 63 minutes using the same formula. For 63 minutes, the z-score is
3 Look up the probabilities for the z-scores in a standard normal distribution table or use a standard normal distribution calculator. The probability for is 0.00298 and the probability for is 0.77337
4 Calculate the probability that the flight time will be between 49 minutes and 63 minutes by subtracting the probability of from the probability of . The probability is 0.77337 - 0.00298 = 0.77039 .
Therefore, the probability that the flight time will be between 49 minutes and 63 minutes is 0.77039.
Therefore, the probability that the flight time will be between 49 minutes and 63 minutes is 0.77039.
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