Solved: 1 point) Suppose the flight time between Montreal and Toronto follows a normal distributi [Statistics]

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1 point) 
Suppose the flight time between Montreal and Toronto follows a normal distribution with an average of 60 minutes and a standard deviation of 4
minutes. Mary is taking a flight tomorrow morning between these two cities. What is the probability that Mary's flight time will be between 49
minutes and 63 minutes? □

1 point) Suppose the flight time between Montreal and Toronto follows a normal distribution with an average of 60 minutes and a standard deviation of 4 minutes. Mary is taking a flight tomorrow morning between these two cities. What is the probability that Mary's flight time will be between 49 minutes and 63 minutes? □

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Expert Verified Solution

0​.77039
1 Calculate the z-score for 49 minutes using the formula z=xμσz = \frac{x - \mu}{\sigma}, where x is the value of interest, μ\mu is the mean, and σ\sigma is the standard deviation. So, for 49 minutes, the z-score is z1=49604=2.75z_1 = \frac{49 - 60}{4} = -2.75
2 Calculate the z-score for 63 minutes using the same formula. For 63 minutes, the z-score is z2=63604=0.75z_2 = \frac{63 - 60}{4} = 0.75
3 Look up the probabilities for the z-scores in a standard normal distribution table or use a standard normal distribution calculator. The probability for z1=2.75z_1 = -2.75 is 0.00298 and the probability for z2=0.75z_2 = 0.75 is 0.77337
4 Calculate the probability that the flight time will be between 49 minutes and 63 minutes by subtracting the probability of z1z_1 from the probability of z2z_2. The probability is 0.77337 - 0.00298 = 0.77039 .
Therefore, the probability that the flight time will be between 49 minutes and 63 minutes is 0.77039.
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